25 ++ sinθ=cos(θ-π/2) 136418-Cos(θ+π/2)=-sinθ 証明

गणना दिया हुआ sinθ = (m 2 – n 2)/(m 2 n 2) and 0 < θ < π/2 यहाँ, हमें cos θ का मूल्य ज्ञात करना हैSin(90˚ θ)=cos θ cos(π/2 θ)=sinθ csc(90˚ θ)=secθ sec(π/2 θ)=cscθ tan(90˚ θ)=cotθ cot(π/2 θ)=tanθFor any θ ∈ ((π/4) , (π/2)), the expression 3( sinθ cosθ)4 6 ( sinθ cosθ)2 4 sin6 θ equals Q For any $\theta \in \left(\frac{\pi}{4} , \frac{\pi}{2}\right),$ the expression $ 3\left(\sin\theta \cos\theta\right)^{4} 6 \left(\sin\theta \cos\theta\right)^{2} 4\sin^{6} \theta $ equals

The Trigonometric Ratios Of Angl

Cos(θ+π/2)=-sinθ 証明

[最も共有された！ √] π^2/6 270362-Sin 1/2=π/6

The polar coordinates of a point are given Plot the point (6, π/2) 10 10 (6, π/2) (6, π/2) 10 5 10 10 10 10 6, /2) (6, π/2) 10 5 10 10 10 10L Find the corresponding rectangular coordinates for the point (x, y) = ( The polar coordinates of a point are givenMedium View solution The number of positive integral solutions of the equation Transcript Ex 33, 3 Prove that cot2 π/6 cosec 5π/6 3 tan2 π/6 = 6 Taking LHS cot2 π/6 cosec 5π/6 3 tan2 π/6 Putting π = 180° = cot2(180/6) cosec((5 ×180)/6) 3 tan2(180/6) = cot2 30° cosec (150°) 3tan2 30° Here, tan 30° = 1/√3 cot 30° = 1/tan⁡〖30°〗 = 1/(1/√3) = √3 For cosec 150° , First, Finding sin 150° sin 150° = sin (180 – 30° ) = sin 30

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Sin 1/2=π/6