गणना दिया हुआ sinθ = (m 2 – n 2)/(m 2 n 2) and 0 < θ < π/2 यहाँ, हमें cos θ का मूल्य ज्ञात करना हैSin(90˚ θ)=cos θ cos(π/2 θ)=sinθ csc(90˚ θ)=secθ sec(π/2 θ)=cscθ tan(90˚ θ)=cotθ cot(π/2 θ)=tanθFor any θ ∈ ((π/4) , (π/2)), the expression 3( sinθ cosθ)4 6 ( sinθ cosθ)2 4 sin6 θ equals Q For any $\theta \in \left(\frac{\pi}{4} , \frac{\pi}{2}\right),$ the expression $ 3\left(\sin\theta \cos\theta\right)^{4} 6 \left(\sin\theta \cos\theta\right)^{2} 4\sin^{6} \theta $ equals
The Trigonometric Ratios Of Angl
